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Mathematics 18 Online
OpenStudy (anonymous):

Rewrite sin x + cos x in the form k sin(x+a) I am LOST HELP ME!!!

OpenStudy (anonymous):

sofar, i got up to this!!

OpenStudy (anonymous):

but i dont know how to get (a)

OpenStudy (anonymous):

ok here are my to cheat sheets, i hope they help

OpenStudy (anonymous):

and try letting\[a=\sqrt{2}\]

OpenStudy (anonymous):

why is it \[\sqrt{2}\] ??

OpenStudy (anonymous):

okay the book said a=pi/4 but i dont know how it got the answer pi/4

jimthompson5910 (jim_thompson5910):

sin(x+a) = sin(x)cos(a)+cos(x)sin(a) Since we want k*sin(x+a) = sin(x) + cos(x) this means k*sin(x+a) = k*(sin(x)cos(a)+cos(x)sin(a)) k*sin(x+a) = k*sin(x)cos(a)+k*cos(x)sin(a) k*sin(x+a) = k*cos(a)*sin(x)+k*sin(a)*cos(x) So k*cos(a) = 1 and k*sin(a) = 1 You can divide the two to get (k*sin(a))/(k*cos(a)) = 1/1 tan(a) = 1

OpenStudy (anonymous):

this is a little tricky ! you found that \[k=\sqrt{2}\]

OpenStudy (anonymous):

\[\cos(a)=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2}\] and \[\sin(a)=\frac{\sqrt{2}}{2}\] so you need to know what is a ? right !

OpenStudy (anonymous):

@lsugano

OpenStudy (anonymous):

yess!

OpenStudy (anonymous):

sorry my internet went down!!

OpenStudy (anonymous):

you don't know how yet ?!

OpenStudy (anonymous):

i dont know how to get (a) but in the book a=pi/4 which i dont know how they got that

OpenStudy (anonymous):

yes ! did you see hamish93's attachements....trig cheat sheet ?!

OpenStudy (anonymous):

yes i did!

OpenStudy (anonymous):

take a look in "the unit circle" !

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i stilll dont get it :(

OpenStudy (anonymous):

you need to commit this to your memory !

OpenStudy (anonymous):

ok...

OpenStudy (anonymous):

w8 ! I'll draw to you something !

OpenStudy (anonymous):

ok! ah thank you so much!!!!

OpenStudy (anonymous):

take a look ! at this !

OpenStudy (anonymous):

\[\text{so } \frac{\pi}{4}<=====> 45°\]

OpenStudy (anonymous):

OH i totally forgot that sin=y cos=x

OpenStudy (anonymous):

makes much more sense!! thank so much for drawing it out for me!

OpenStudy (anonymous):

you have to commit the unit Circl to your memory.....(the one in the Trig Cheat Sheet )

OpenStudy (anonymous):

okay!! i will try my besttt!

OpenStudy (anonymous):

Very Good :) !

OpenStudy (anonymous):

thank you!!

OpenStudy (anonymous):

im going to try another example like this could you please check if your not busy?

OpenStudy (anonymous):

you're welcome !and I'm never busy !

OpenStudy (anonymous):

the example ?!

OpenStudy (anonymous):

i am almost done with my first step!!

OpenStudy (anonymous):

so the question is y=sinx + √3cosx to the form ksin(x+a) a=radians

OpenStudy (anonymous):

kk !

OpenStudy (anonymous):

my first step looks like this!

OpenStudy (anonymous):

now ! find "a" using the unit circle !

OpenStudy (anonymous):

!!!!!!!

OpenStudy (anonymous):

Very good ! that's correct ! you're brilliant ! :)

OpenStudy (anonymous):

:) feels good to get the right answer! lol

OpenStudy (anonymous):

since i was struggling with most of all the problems i feel happy right now/

OpenStudy (anonymous):

yeaah :) :) and I feel happy for you !

OpenStudy (anonymous):

thank you so much!!

OpenStudy (anonymous):

:) It's been a pleasure ! :)

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