Rewrite sin x + cos x in the form k sin(x+a) I am LOST HELP ME!!!
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OpenStudy (anonymous):
sofar, i got up to this!!
OpenStudy (anonymous):
but i dont know how to get (a)
OpenStudy (anonymous):
ok here are my to cheat sheets, i hope they help
OpenStudy (anonymous):
and try letting\[a=\sqrt{2}\]
OpenStudy (anonymous):
why is it \[\sqrt{2}\] ??
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OpenStudy (anonymous):
okay the book said a=pi/4 but i dont know how it got the answer pi/4
jimthompson5910 (jim_thompson5910):
sin(x+a) = sin(x)cos(a)+cos(x)sin(a)
Since we want
k*sin(x+a) = sin(x) + cos(x)
this means
k*sin(x+a) = k*(sin(x)cos(a)+cos(x)sin(a))
k*sin(x+a) = k*sin(x)cos(a)+k*cos(x)sin(a)
k*sin(x+a) = k*cos(a)*sin(x)+k*sin(a)*cos(x)
So k*cos(a) = 1 and k*sin(a) = 1
You can divide the two to get
(k*sin(a))/(k*cos(a)) = 1/1
tan(a) = 1
OpenStudy (anonymous):
this is a little tricky !
you found that \[k=\sqrt{2}\]
OpenStudy (anonymous):
\[\cos(a)=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2}\]
and \[\sin(a)=\frac{\sqrt{2}}{2}\]
so you need to know what is a ? right !
OpenStudy (anonymous):
@lsugano
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OpenStudy (anonymous):
yess!
OpenStudy (anonymous):
sorry my internet went down!!
OpenStudy (anonymous):
you don't know how yet ?!
OpenStudy (anonymous):
i dont know how to get (a) but in the book a=pi/4 which i dont know how they got that
OpenStudy (anonymous):
yes ! did you see hamish93's attachements....trig cheat sheet ?!
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OpenStudy (anonymous):
yes i did!
OpenStudy (anonymous):
take a look in "the unit circle" !
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i stilll dont get it :(
OpenStudy (anonymous):
you need to commit this to your memory !
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OpenStudy (anonymous):
ok...
OpenStudy (anonymous):
w8 ! I'll draw to you something !
OpenStudy (anonymous):
ok! ah thank you so much!!!!
OpenStudy (anonymous):
take a look ! at this !
OpenStudy (anonymous):
\[\text{so } \frac{\pi}{4}<=====> 45°\]
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OpenStudy (anonymous):
OH i totally forgot that sin=y cos=x
OpenStudy (anonymous):
makes much more sense!! thank so much for drawing it out for me!
OpenStudy (anonymous):
you have to commit the unit Circl to your memory.....(the one in the Trig Cheat Sheet )
OpenStudy (anonymous):
okay!! i will try my besttt!
OpenStudy (anonymous):
Very Good :) !
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OpenStudy (anonymous):
thank you!!
OpenStudy (anonymous):
im going to try another example like this could you please check if your not busy?
OpenStudy (anonymous):
you're welcome !and I'm never busy !
OpenStudy (anonymous):
the example ?!
OpenStudy (anonymous):
i am almost done with my first step!!
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OpenStudy (anonymous):
so the question is y=sinx + √3cosx to the form ksin(x+a) a=radians
OpenStudy (anonymous):
kk !
OpenStudy (anonymous):
my first step looks like this!
OpenStudy (anonymous):
now ! find "a" using the unit circle !
OpenStudy (anonymous):
!!!!!!!
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OpenStudy (anonymous):
Very good ! that's correct !
you're brilliant ! :)
OpenStudy (anonymous):
:) feels good to get the right answer! lol
OpenStudy (anonymous):
since i was struggling with most of all the problems i feel happy right now/
OpenStudy (anonymous):
yeaah :) :) and I feel happy for you !
OpenStudy (anonymous):
thank you so much!!
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