Question

integral [ cos^4(x) sin^3(x) ] dx. show steps.

Answer 1

\[\int \cos^{4} x\ \sin ^{3} x\ dx\]
Let's rewrite this
\[\int \cos^{4} x\ \sin x\ \sin ^{2} x\ dx\]
we know that \(\sin ^2 x= 1-\cos^2 x\) , we get
\[\int \cos^{4} x\ \sin x\ (1-\cos ^{2} x)\ dx\]
Now let's substitute
\[\cos x=t\]
we get
\[-\sin x\ dx=dt\]
so our integral changes to
\[\large \int t^4(1-t^2) -dt\]
Can you take it from here?
@alienbrain

Answer 2

umm

Answer 3

i'm not sure, please continue.

Answer 4

take a look at this
http://tutorial.math.lamar.edu/pdf/Calculus_Cheat_Sheet_Integrals_Reduced.pdf

Answer 5

wow, that's pretty cool!

Answer 6

see...Products and (some) Quotients of Trig Functions first page !

Answer 7

love the process breakdown

Answer 8

ok, i should be good. thanks

Answer 9

yw !