Question

factorize: a2+b2-2(ab-ac+bc)

Answer 1

check it again @basith is it :

\[\large{a^2+b^2+c^2-2(ab-ac+bc)}\]
\[\large{a^2+b^2-c^2-2(ab-ac+bc)}\]

Answer 2

which one?

Answer 3

\[{\large(a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)}\]

Answer 4

\[a ^{2}+b ^{2}-2(ab-ac+bc)\]

Answer 5

ok .. :
\[{a^2+b^2-2(ab-ac+bc)=a^2+b^2-2ab+2ac-2bc}\]
\[\large{=a^2-2ab+b^2-2bc+2ac}\]

Answer 6

\[\large{a(a-2b)+b(b-2c)+2ac}\]

Answer 7

a^2 - 2ab + b^2 -2bc + 2ac
= (a-b)^2 + c(a-b)
= (a-b)(a-b+c)

Answer 8

got it??

Answer 9

\[\large{a^2-2ab+b^2-2bc+2ac}\]
\[\large{(a-b)^2+2c(a-b)}\]
\[\large{(a-b)(a-b+2c)}\]

good work @Neo92

Answer 10

@basith got it?

Answer 11

@ mathsolver
thnx.. i missed da 2 there..

Answer 12

no problem ..

Answer 13

i have a doubt @mathslover

Answer 14

ask @basith

Answer 15

how did u get.....
\[(a-b)(a-b+2c)\]

Answer 16

i took (a-b) common

Answer 17

i was having:
\[\large{(a-b)^2+2c(a-b)}\]
\[\large{(a-b)(a-b)+2c(a-b)}\]
\[\large{(a-b)(a-b+2c)}\]

Answer 18

(a-b)(a-b+2c)
u can see
http://www.wolframalpha.com/input/?i=factorize%3A+a2%2Bb2-2%28ab-ac%2Bbc%29