Question

y = ax^2 + bx + c
Determine the solution set of 0 = ax^2 + bx + c.

is it {-2} ?

Answer 1

do you know how to calculate the solution set?

Answer 2

i yesterday posted solution o the same problem.
you can check it here
http://openstudy.com/study#/updates/5015fdf9e4b0fa246733cc56

Answer 3

It is actually a lot more related to the quadratic formula.

Answer 4

In a quadratic equation \(ax^2 + bx + c = 0\), there are two roots. Do you know the quadratic formula?

Answer 5

@helpme9283 did you get it?

Answer 6

Remember: the two roots are given as follows. \[\alpha = {-b + \sqrt{b^2 - 4ac} \over 2a} \] \[\beta = {-b - \sqrt{b^2 - 4ac}\over 2a} \]

Answer 7

Does that give you a nice hint?

Answer 8

here it is when y=0
ax^2+bx+c=0
then using by completing square method solution is as follows.

Answer 9

Solution set consists of numbers that are solutions.
For example, if 2 and 3 are the solutions, then the solution set it \((2,3)\).

Answer 10

What are the solutions that I gave you?

Answer 11

2&3

Answer 12

No. What are the solutions that I gave you for \(ax^2 + bx + c = 0\)?

Answer 13

i didnt get it..

Answer 14

Read the post where I mentioned alpha and beta.

Answer 15

this is the solution set.
\[\Large [{\frac{-b+\sqrt{b^2-4ac}}{2a}} ,{\frac{-b-\sqrt{b^2-4ac}}{2a}}]\]

Answer 16

Oh-oh.

Answer 17

or :
\[\LARGE{roots=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}\]

Answer 18

But that is not the solution set.

Answer 19

@sami-21 Is right, but should consider not posting answers :)