If I was simplifying (4x^3 + 3x^2 − 6x) − (10x^3 + 3x^2) would the answer be 14x^3 + 6x^2 - 6x
becareful of the "-"
no 4-10 =-6 just check
it distributes thru the (...) and flips all the signs
Distributing a '-' is more like distributing a '-1'. Got it?
For example, \(-(2x + 3) \Longrightarrow -1(2x + 3) \Longrightarrow (-1)(2x) + (-1)(3) \) Which gets you \(-2x - 3\).
so (10x^3 + 3x^2) is now (-10x^3 - 3x^2)?
correct
Exactly!
okay, is the first part left alone?
Yep.
it helps me to stack things up (4x^3 + 3x^2 − 6x) − (10x^3 + 3x^2) 4x^3 + 3x^2 − 6x -10x^3 - 3x^2 -------------------- then just combine
It has no '-' sign. It instead has a + sign, which means distributing a +1. \(+(a -b) = +1(a - b) = +a - b = a-b\)
would the answer be -6x^3 - x^2 - 6x? or is it a positive x^2
4x^3 + 3x^2 − 6x -10x^3 - 3x^2 --------------------
what is 3-3?
Remember: \(3x^2 - 3x^2 = 0\)
so would it just be eliminated from the problem or just be like x or something?
That comes right from \[3x^2 - 3x^2 \rightarrow (3 - 3)x^2 \rightarrow 0x^2 = 0 \]
Yeah, it'd just get removed like breeze.
0x^2 = 0 by the rule that says when we multiply by zero we end up with zero
Okay! I understand, thank you guys so much it means a lot!
good luck :)
You're welcome :) I was just a sidekick for amistre heh
Parth is my conscience, when i go mathically astray he laughs at me lol
I need a dictionary for that at the moment. Be right back!
go - it is the present tense of went ;)
lol :)
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