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3/4x+1=x+4
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is it:\[\frac{3}{4x+1} = x+1\] OR \[\frac{3}{4x} + 1 = x+4\]
the second one!!
ok, subtract 1 from each side:\[\frac{3}{4x} = x+3\]Then multiply both sides by 4x:\[3 = 4x(x+3)\]Simplify to:\[3=4x^2 + 12x\]Can you solve it from here?
from there do i add 12z to 4z??
no, you make it a quadratic (complete the square)\[3 = 4(x^2 + 12x) \rightarrow 3+4(36) = 4(x^2 + 12x + 36) \rightarrow 147 = 4(x+6)^2\]Then: \[\frac{147}{4} = (x+6)^2 \rightarrow x+6 = \pm \sqrt{\frac{147}{4}} \rightarrow x = -6 \pm \frac{\sqrt{147}}{2}\]
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i need help @moser90 !!
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