HELLPPPP!!!! PLLLEEZZ!! :)) Which of the following is the solution to the equation sqrt5^8n = 125^(n + 5) ? n=5,n=-5,n=15,n=-15?
\[ \large \sqrt{5}^{8n}=125^{n+5} \] ??
u can see here http://www.wolframalpha.com/input/?i=sqrt5%5E8n+%3D+125%5E%28n+%2B+5%29
@helder_edwin yah thats right ;)
Ok first \[ \large \sqrt{5}^{8n}=(5^{1/2})^{8n}=5^{1/2\cdot8n}=5^{4n} \] OK?
yah!
then \[ \large 125^{n+5}=(5^3)^{n+5}=5^{3(n+5)}=5^{3n+15} \]
so \[ \large \sqrt{5}^{8n}=12^{n+5} \] becomes \[ \large 5^{4n}=5^{3n+15} \]
agree?
ok... but where did 12 come from?
sorrry 125 not 12
ok!! yah i understand so far! ;)
now we have this \[ \large A^x=A^y\qquad\Rightarrow\qquad x=y \]
this means that \[ \large 5^{4n}=5^{3n+15} \] becomes \[ \large 4n=3n+15 \]
u can finish this right?
|dw:1343838748109:dw|so its right?
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