Ask
your own question, for FREE!
Mathematics
21 Online
OpenStudy (anonymous):
HELLPPPP!!!! PLLLEEZZ!! :))
Which of the following is the solution to the equation sqrt5^8n = 125^(n + 5) ?
n=5,n=-5,n=15,n=-15?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (helder_edwin):
\[ \large \sqrt{5}^{8n}=125^{n+5} \]
??
OpenStudy (anonymous):
@helder_edwin yah thats right ;)
OpenStudy (helder_edwin):
Ok first
\[ \large \sqrt{5}^{8n}=(5^{1/2})^{8n}=5^{1/2\cdot8n}=5^{4n} \]
OK?
OpenStudy (anonymous):
yah!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (helder_edwin):
then
\[ \large 125^{n+5}=(5^3)^{n+5}=5^{3(n+5)}=5^{3n+15} \]
OpenStudy (helder_edwin):
so
\[ \large \sqrt{5}^{8n}=12^{n+5} \]
becomes
\[ \large 5^{4n}=5^{3n+15} \]
OpenStudy (helder_edwin):
agree?
OpenStudy (anonymous):
ok... but where did 12 come from?
OpenStudy (helder_edwin):
sorrry 125 not 12
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok!! yah i understand so far! ;)
OpenStudy (helder_edwin):
now we have this
\[ \large A^x=A^y\qquad\Rightarrow\qquad x=y \]
OpenStudy (helder_edwin):
this means that
\[ \large 5^{4n}=5^{3n+15} \]
becomes
\[ \large 4n=3n+15 \]
OpenStudy (helder_edwin):
u can finish this
right?
OpenStudy (anonymous):
|dw:1343838748109:dw|so its right?
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!