Question

How much work is required to lift an object with a mas of 5.0 kilograms to a height of 3.5 meters?

Answer 1

work done = potential energy stored = mgh = 5*10*3.6= 180N

Answer 2

But the answer chooses are
A.17 joules
B.1.7 × 10^2 joules
C.1.9 × 10^2 joules
D.2.8 × 10^2 joules

Answer 3

well i guess options are incorrect....or else you can convert 180 N into joules 1joule= 1 n-m

Answer 4

Wow ok thank you I will go tell her this

Answer 5

anytime

Answer 6

1.76*10^2 joules

Answer 7

work done = potential energy stored = mgh = 5*9.8*3.6= 11760N-m or 1.76*10^2joules
@jrkiller

Answer 8

@ghazi the unit for work is joules, not newtons. so ur ans will anyway be in J.
@theyatin ur ans should be 176.4. J....not 11760 N-m.
@jrkiller as theyatin said, the ans is opt B. there is a difference between theyatin and ghazi's answer, because both took different values of g. ghazi took g=10 and theyatin took g=9.8.

Answer 9

yea i forgot to write N-m

Answer 10

@Vaidehi09 its a type ddear i wanted to type 1760 just to round off dont be so rude to kids ;'(

Answer 11

@theyatin did i sound rude?! sorry...no intention to!!

Answer 12

lol bacha i was kidding :)
just don't give so much stress on correcting others . . .

Answer 13

@ghazi no offense to u too!!
@theyatin right. i'll be careful from now on. thanks! :)

Answer 14

@Vaidehi09 it's cool

Answer 15

@ghazi :) thanks.