Question

x2 + 8x = 24

Answer 1

move the 24 over to the other side and set then factor them...then set those binomials equal to zero and solve for x

Answer 2

\[x^{2}+8x=24\]
\[(x+4)^{2}-16=24\]
\[(x+4)^{2}-40=0\]
\[(x+4+\sqrt{40})(x+4-\sqrt{40})\]
\[(x+4+2\sqrt{10})(x+4-2\sqrt{10})\]

Answer 3

understood all the steps?

Answer 4

got it thanks :D