Calculate the equation of the line between the points (-6, -1) and (2, -1)
What is the standard equation of a line? y=mx+b. m is the slope, it is rise/run and b is the y-intercept. Try drawing it out to see if this helps.
I tried yet I dont understand.
Well, what does your picture look like? How much do you rise and how much do you run to get from one point to the next? Where on the y-axis is the line touching at x=0?
Some what above -1?
(-6, -1) and (2, -1) First find the slope of the line: y - y over x - x Once you find the slope try putting it into point-slope form: y - y1 = m(x - x1)
After that you can change it easily from point-slope to standard form.
Im completely lost.
Do you want to do it the way I mentioned above? Step by step?
Yes please
Ok, so first lets find the slope: The formula to find slope is the difference between the y points over the difference between the x points.
So the one furthest to the right is Y2? And X2?
Look at your given points: (-6, -1) and (2, -1) y values: -1 and -1 x values: 2 and -6
Okay
So find the difference between the y-values: -1 - (-1)
Jeremiah, I know this might take 30 minutes, but really play around with a graph of y based on x being multiplied with numbers and being added to numbers. Then you'll understand why y=mx+b. What is the difference between the graphs y=2x and y=x? What is the difference between y=x+1 and y=x? If you spend the time to figure this out you will understand and maybe even be able to answer your own questions! =D
2
I agree with @Kainui when you put these points on a graph it is definately easier to spot out the equation:) Check again: Try -1 + 1 (two - signs equal a +)
0
sorry i did that and I thoughh it said 1+1
Yes. And 2 + 6?
8
0/8
Exactly! You see how there is a 0 in the numerator. Remember rise/run: so the line doesn't rise. The slope is 0.
B is slope right or is it m?
The line is a horizontal line. m = slope b = y-intercept
So whats y and x?
Ok so now we have the slope and we can make the point-slope equation, This is quick and easy:)
Pick one of the two original points (-6, -1) or (2, -1)
Whats the Y intercept?
y-intercept is where the line crosses the y-axis. But in order to get to standard form (y = mx + b) you should put an equation is point-slope form(y - y1 = m(x - x1) So you pick one point. Lets go with (-6, -1). Now just substitute the values into the equation: (-6, -1) m= slope = 0 y - (-1) = 0(x - (-6)) y + 1 = 0(x + 6)
**The y1 and x1 are where you put in the values of x and y
so the final equation Im geussing would end up bein y=-8x-1?
no. Remember that the m in y = mx + b is the slope. And we found that the slope was 0. But your y-inercept(b) is correct:) Try simplifying this: First you must distribute the 0 into the x and the 6... y + 1 = 0(x + 6) y + 1 = (0 * x) + (0 * 6) Keep in mind that you can never elliminate the x; 0 * x would be 0x
so what would it be?
So it would be: y + 1 = 0x Now you just want to leave the y alone on one side so subtract the 1 from both sides of the equation: y + 1 - 1 = 0x -1 y = 0x - 1 Final answer: The equation of the line between the points (-6, -1) and (2, -1) would be: \[y = 0x + 1\]
Thats not one of the choices though
What are your choices? Sorry it took so long to explain:) It looks complicated at first but it gets a lot easier after you do it a lot.
a. y = -1 b. x = -1 c. y = -8x - 1 d. y = -x - 8
A) y = -1 Sorry I had forgotten that when a line is horizontal the answer is just y = and the y-intercept.... Whenever you want to check an equation i suggest you use this: https://www.desmos.com/calculator Just put in the equation(doesn't matter the format) and it shows the line. Out of curiosity, are you in FLVS?
Oh no Im in BYU
Oh ok:) I was asking cuz I took Algebra in FLVS last semester; and this was pretty much what I came to ask at openstudy every day until I got the hang of it:D
Hope I helped, as confusing as it might have been...:) And I hope you do well on your classes!
Join our real-time social learning platform and learn together with your friends!