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Mathematics 17 Online
OpenStudy (anonymous):

Cos2x + 2sinx = 0

OpenStudy (anonymous):

I need help will anyone help?

OpenStudy (anonymous):

What do you want to do ??

OpenStudy (anonymous):

What is your question??

OpenStudy (anonymous):

This is the simple equation you have written.. What we are to find here ??

OpenStudy (anonymous):

I am assuming that you have to find sinx here..

OpenStudy (anonymous):

\[\cos(2x) = 1 - \sin^2(x)\] So: \[1 - 2 \sin^2(x) + \sin(x) = 0 \implies 2\sin^2(x) - \sin(x) - 1 = 0\]

OpenStudy (anonymous):

Waterineyes I have a question how come the -2sin^2x becomes positive?

OpenStudy (anonymous):

Here you can factorize it: \[2\sin^2(x) - 2\sin(x) + \sin(x) - 1 = 0 \implies 2\sin(x)(\sin(x) -1) + 1(\sin(x) - 1) = 0\] \[\sin(x) - 1 = 0 \qquad Or \qquad 2\sin(x) + 1 = 0\]

OpenStudy (anonymous):

@Brendan97 I have multiplied by (-1) both the sides..

OpenStudy (anonymous):

No no no... see I have to find all solutions in the interval from 0 to 2pie , buyt I can't see yourt responses... and oh... I am a little slow sorry

OpenStudy (anonymous):

I have to find all solutions and they are all crazy solutions like 5.908, and 3.516 How do I acquire that.. I am a frshman taking pre-calc and I have no teacher so I struggle.. if you could slowly explain the steps plz

OpenStudy (anonymous):

you there?

OpenStudy (anonymous):

\[\cos(2x) = 1 - 2\sin^2(x)\]

OpenStudy (anonymous):

Yes I know that double angle identity so I understand that , but the soltuions shown on my paper I don't understand how to get any of them

OpenStudy (anonymous):

So plug this in place of cos(2x)..

OpenStudy (anonymous):

I explain you wait..

OpenStudy (anonymous):

\[\sin(x) - 1 = 0 \qquad Or \qquad 2\sin(x) + 1 = 0\] Can I explain after this ??

OpenStudy (anonymous):

alright well I have all that and then I use quadratic formula and I get 2 (+ or -) sqrt12 / 4

OpenStudy (anonymous):

Why you get those solutions and not quadratic formula?

OpenStudy (anonymous):

there is no need to use quadratic formula.. We can use factorization here..

OpenStudy (anonymous):

I show you by quadratic formula so that I can check you are correct or not.

OpenStudy (anonymous):

but your solutions are not what my papre shows.. quadratic formula gives me 1 plus or minus the square root of 3 divided by 2

OpenStudy (anonymous):

\[2\sin^2(x) - \sin(x) - 1 = 0\] \[\sin(x) = \frac{1 \pm \sqrt{9}}{2 \times 2} \implies \sin(x) = \frac{1 \pm 3}{4}\]

OpenStudy (anonymous):

My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726

OpenStudy (anonymous):

Water how you get square root of 3? In my quadratic equation A = 2 B= -2 C = -1? HBY?

OpenStudy (anonymous):

Therefore: \[\sin(x) = 1 \qquad Or \qquad \sin(x) = \frac{-1}{2}\]

OpenStudy (anonymous):

My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726

OpenStudy (anonymous):

Which answer is it then?

OpenStudy (anonymous):

B is -1 and not -2..

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

2sin^2x - 2sinx -1 = 0 is the problem

OpenStudy (anonymous):

\[2\sin^2(x) - \sin(x) -1 = 0\]

OpenStudy (anonymous):

no see you must have accidently gotten the wrong problem.. it's cos2x + 2sinx = 0

OpenStudy (anonymous):

Sorry then I have to write it again..

OpenStudy (anonymous):

Just wait..

OpenStudy (anonymous):

yeah it's okay I wish we had msn so we could reply faster

OpenStudy (anonymous):

\[2\sin^2(x) - 2\sin(x) -1 = 0\] \[\sin(x) = \frac{2 \pm \sqrt{12}}{4} \implies \sin(x) = \frac{1 \pm \sqrt{3}}{2}\]

OpenStudy (anonymous):

Yup that is exactly what I have :) Now how do I use that to get these answers>? My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726

OpenStudy (anonymous):

Wait let me check first..

OpenStudy (anonymous):

water are you in pre-calc?

OpenStudy (anonymous):

I am in college.. And I am not generally study these things.. I had read them 4 years back..

OpenStudy (anonymous):

oh.. uhm well this sucks .. see once you get that anxswer you have to find which one it is and I can never find and help so today I discovered this website hoping for help... looks like I am stuck for ever

OpenStudy (anonymous):

:/

OpenStudy (anonymous):

See we can separate this like: \[\sin(x) = \frac{1 + \sqrt{3}}{2} \implies \sin(x) = 1.366\] \[\sin(x) = \frac{1 - \sqrt{3}}{2} \implies \sin(x) = -0.366\]

OpenStudy (anonymous):

Now we have to find x here..

OpenStudy (anonymous):

Yeah but solutionsa re solutions to sin(x) , but the x is these numbers... the answer is some degree measurement on the unit circle but I can't figure out how to calculate . opnline it says 1.366 cannot be possible because it;'s outside but some measure of .366 is our answer

OpenStudy (anonymous):

where ever sinx = .366 I think not sure?

OpenStudy (anonymous):

gg this is so depressing .. no one can help me.. I have no damn teacher and I just wana quit.. :'( FFS

OpenStudy (anonymous):

You there? If not.. this is just bs L.

OpenStudy (anonymous):

Wait..

OpenStudy (anonymous):

alright sorry I am just depressed I have been wroking for weeks on this question and my course ends soon I am gonna faikl :/

OpenStudy (anonymous):

First one is not possible..

OpenStudy (anonymous):

Water the first one : My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726 A is the answer

OpenStudy (anonymous):

I need to know how to do it so I acan advance in life..

OpenStudy (anonymous):

Go with second: \[\sin(x) = -0.366 \implies x = -21.48\]

OpenStudy (anonymous):

The answer is the first one.. , but I have no idea how to find it... I found answer online somewhere

OpenStudy (anonymous):

See you can write it now as: \[\sin(x) = -\sin(21.48)\]

OpenStudy (anonymous):

Let me try first with full my satisfaction..

OpenStudy (anonymous):

hmm?

OpenStudy (anonymous):

\[\sin(x) = \sin(-21.48) \implies \sin(x) = \sin(-0.12 \pi)\]

OpenStudy (anonymous):

I have converted degree into radians..

OpenStudy (anonymous):

Water but that is not the right answer :/ My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726

OpenStudy (anonymous):

\[\large x = n \pi + (-1)^n (-0.12 \pi)\]

OpenStudy (anonymous):

Here put n = 1 here and find x..

OpenStudy (anonymous):

?

OpenStudy (anonymous):

I got 3.51628 on putting n = 1 here..

OpenStudy (anonymous):

3.519 close where you get that formula?

OpenStudy (anonymous):

These are the general formula I will give you the link I have given tutorial on this topic today only.. Now put n = 2..

OpenStudy (anonymous):

n = 2 gives me 6.245 u?

OpenStudy (anonymous):

5.9032..

OpenStudy (anonymous):

i show you I think you messed up with negative sign there..

OpenStudy (anonymous):

how you type in calc? I type 1(Pie) + (-1)^1(-.012pie)

OpenStudy (anonymous):

\[x = 2\pi + (-1)^2 (-0.12 \pi) \implies 2 \pi - 0.12 \pi = ??\]

OpenStudy (anonymous):

I am doing normally with my mobile..

OpenStudy (anonymous):

yeah, but how you do that for 1?

OpenStudy (anonymous):

wait 2(pie) =6.283

OpenStudy (anonymous):

\[\large x = \pi + (-1)^1 (-0.12\pi) \implies x = \pi - (-0.12 \pi) \implies \pi + 0.12 \pi\]

OpenStudy (anonymous):

-.12(Pie) =.377

OpenStudy (anonymous):

Check it for 2pie @Brendan97 you are doing mistake in calculation I guess..

OpenStudy (anonymous):

Where is negative sign ??

OpenStudy (anonymous):

5.906 for 2(pie)( and 3.519 for 1 :) Is that correct?

OpenStudy (anonymous):

Yes it is correct..

OpenStudy (anonymous):

but how did you come up with that random formula and apply it to my problem?

OpenStudy (anonymous):

http://openstudy.com/updates/5018d167e4b04dfc808c85e1 Try to study every part here.. Hope this will add something to your knowledge..

OpenStudy (anonymous):

wait can you just explain

OpenStudy (anonymous):

I have explained everything there please read once on your own.. Here its 2:21 in the morning..

OpenStudy (anonymous):

all I see is like code for color blue and stuff?

OpenStudy (anonymous):

all I see is like code for color blue and stuff?

OpenStudy (anonymous):

it's not displaying properly

OpenStudy (anonymous):

Reload your page and then see..

OpenStudy (anonymous):

There check the Second Form (1) that is explaining your formula..

OpenStudy (anonymous):

same it's says like color red theta and stuff... ugg :/well this was no help... can I get like that fiormula?

OpenStudy (anonymous):

how did you get that .12(pie) at that end of the formula?

OpenStudy (anonymous):

I have converted -21.48 to radians by multiplying it with pie by 180..

OpenStudy (anonymous):

how did you get -21.48?

OpenStudy (anonymous):

\[-21.48 \times \frac{\pi}{180} \implies -0.12 \pi\]

OpenStudy (anonymous):

Can you retype me that formula?

OpenStudy (anonymous):

\[\sin(x) = -0.366 \implies x = \sin^{-1}(-0.366) = -21.48\]

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