Cos2x + 2sinx = 0
I need help will anyone help?
What do you want to do ??
What is your question??
This is the simple equation you have written.. What we are to find here ??
I am assuming that you have to find sinx here..
\[\cos(2x) = 1 - \sin^2(x)\] So: \[1 - 2 \sin^2(x) + \sin(x) = 0 \implies 2\sin^2(x) - \sin(x) - 1 = 0\]
Waterineyes I have a question how come the -2sin^2x becomes positive?
Here you can factorize it: \[2\sin^2(x) - 2\sin(x) + \sin(x) - 1 = 0 \implies 2\sin(x)(\sin(x) -1) + 1(\sin(x) - 1) = 0\] \[\sin(x) - 1 = 0 \qquad Or \qquad 2\sin(x) + 1 = 0\]
@Brendan97 I have multiplied by (-1) both the sides..
No no no... see I have to find all solutions in the interval from 0 to 2pie , buyt I can't see yourt responses... and oh... I am a little slow sorry
I have to find all solutions and they are all crazy solutions like 5.908, and 3.516 How do I acquire that.. I am a frshman taking pre-calc and I have no teacher so I struggle.. if you could slowly explain the steps plz
you there?
\[\cos(2x) = 1 - 2\sin^2(x)\]
Yes I know that double angle identity so I understand that , but the soltuions shown on my paper I don't understand how to get any of them
So plug this in place of cos(2x)..
I explain you wait..
\[\sin(x) - 1 = 0 \qquad Or \qquad 2\sin(x) + 1 = 0\] Can I explain after this ??
alright well I have all that and then I use quadratic formula and I get 2 (+ or -) sqrt12 / 4
Why you get those solutions and not quadratic formula?
there is no need to use quadratic formula.. We can use factorization here..
I show you by quadratic formula so that I can check you are correct or not.
but your solutions are not what my papre shows.. quadratic formula gives me 1 plus or minus the square root of 3 divided by 2
\[2\sin^2(x) - \sin(x) - 1 = 0\] \[\sin(x) = \frac{1 \pm \sqrt{9}}{2 \times 2} \implies \sin(x) = \frac{1 \pm 3}{4}\]
My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726
Water how you get square root of 3? In my quadratic equation A = 2 B= -2 C = -1? HBY?
Therefore: \[\sin(x) = 1 \qquad Or \qquad \sin(x) = \frac{-1}{2}\]
My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726
Which answer is it then?
B is -1 and not -2..
how?
2sin^2x - 2sinx -1 = 0 is the problem
\[2\sin^2(x) - \sin(x) -1 = 0\]
no see you must have accidently gotten the wrong problem.. it's cos2x + 2sinx = 0
Sorry then I have to write it again..
Just wait..
yeah it's okay I wish we had msn so we could reply faster
\[2\sin^2(x) - 2\sin(x) -1 = 0\] \[\sin(x) = \frac{2 \pm \sqrt{12}}{4} \implies \sin(x) = \frac{1 \pm \sqrt{3}}{2}\]
Yup that is exactly what I have :) Now how do I use that to get these answers>? My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726
Wait let me check first..
water are you in pre-calc?
I am in college.. And I am not generally study these things.. I had read them 4 years back..
oh.. uhm well this sucks .. see once you get that anxswer you have to find which one it is and I can never find and help so today I discovered this website hoping for help... looks like I am stuck for ever
:/
See we can separate this like: \[\sin(x) = \frac{1 + \sqrt{3}}{2} \implies \sin(x) = 1.366\] \[\sin(x) = \frac{1 - \sqrt{3}}{2} \implies \sin(x) = -0.366\]
Now we have to find x here..
Yeah but solutionsa re solutions to sin(x) , but the x is these numbers... the answer is some degree measurement on the unit circle but I can't figure out how to calculate . opnline it says 1.366 cannot be possible because it;'s outside but some measure of .366 is our answer
where ever sinx = .366 I think not sure?
gg this is so depressing .. no one can help me.. I have no damn teacher and I just wana quit.. :'( FFS
You there? If not.. this is just bs L.
Wait..
alright sorry I am just depressed I have been wroking for weeks on this question and my course ends soon I am gonna faikl :/
First one is not possible..
Water the first one : My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726 A is the answer
I need to know how to do it so I acan advance in life..
Go with second: \[\sin(x) = -0.366 \implies x = -21.48\]
The answer is the first one.. , but I have no idea how to find it... I found answer online somewhere
See you can write it now as: \[\sin(x) = -\sin(21.48)\]
Let me try first with full my satisfaction..
hmm?
\[\sin(x) = \sin(-21.48) \implies \sin(x) = \sin(-0.12 \pi)\]
I have converted degree into radians..
Water but that is not the right answer :/ My answers for this questions are: A) 5.908,3.516 B) 4.084, 1.726 C) 5.908 D) 1.726
\[\large x = n \pi + (-1)^n (-0.12 \pi)\]
Here put n = 1 here and find x..
?
I got 3.51628 on putting n = 1 here..
3.519 close where you get that formula?
These are the general formula I will give you the link I have given tutorial on this topic today only.. Now put n = 2..
n = 2 gives me 6.245 u?
5.9032..
i show you I think you messed up with negative sign there..
how you type in calc? I type 1(Pie) + (-1)^1(-.012pie)
\[x = 2\pi + (-1)^2 (-0.12 \pi) \implies 2 \pi - 0.12 \pi = ??\]
I am doing normally with my mobile..
yeah, but how you do that for 1?
wait 2(pie) =6.283
\[\large x = \pi + (-1)^1 (-0.12\pi) \implies x = \pi - (-0.12 \pi) \implies \pi + 0.12 \pi\]
-.12(Pie) =.377
Check it for 2pie @Brendan97 you are doing mistake in calculation I guess..
Where is negative sign ??
5.906 for 2(pie)( and 3.519 for 1 :) Is that correct?
Yes it is correct..
but how did you come up with that random formula and apply it to my problem?
http://openstudy.com/updates/5018d167e4b04dfc808c85e1 Try to study every part here.. Hope this will add something to your knowledge..
wait can you just explain
I have explained everything there please read once on your own.. Here its 2:21 in the morning..
all I see is like code for color blue and stuff?
all I see is like code for color blue and stuff?
it's not displaying properly
Reload your page and then see..
There check the Second Form (1) that is explaining your formula..
same it's says like color red theta and stuff... ugg :/well this was no help... can I get like that fiormula?
how did you get that .12(pie) at that end of the formula?
I have converted -21.48 to radians by multiplying it with pie by 180..
how did you get -21.48?
\[-21.48 \times \frac{\pi}{180} \implies -0.12 \pi\]
Can you retype me that formula?
\[\sin(x) = -0.366 \implies x = \sin^{-1}(-0.366) = -21.48\]
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