what is the simplified form of 11sqrt(8)+6sqrt(12)-5sqrt(2)

Question

campbell_st · Answer

you need to write each radical as a multiple of sqrt(2)

$$\sqrt{8} = \sqrt{4\times2} = \sqrt{4}\times \sqrt{2} = 2\sqrt{2}$$

so $$11\sqrt{8} = 11\times2\sqrt{2} = 22\sqrt{2}$$

you need to do the same type of thing for 

$$6\sqrt{12}$$

campbell_st · Answer

not quite.... here is the start

$$6\sqrt{12} = 6\sqrt{4 \times3}$$

so in your question you will have 2 like terms, (sqrt(2) and one that is sqrt(3)

campbell_st · Answer

so at the moment you have 

$$22\sqrt{2} + 6\sqrt{4\times3} - 5\sqrt{2}$$

anonymous · Answer

okay

campbell_st · Answer

then you have 

$$(22 - 5)\sqrt{2} + 6\sqrt{4\times3}$$

anonymous · Answer

okay

campbell_st · Answer

$$17\sqrt{2} + 6\sqrt{4}\times \sqrt{3}$$

I'll let you finish it

anonymous · Answer

well what would i do because there's no like terms?

campbell_st · Answer

$$17\sqrt{2} + 12\sqrt{3}$$