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what is the simplified form of 11sqrt(8)+6sqrt(12)-5sqrt(2)
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you need to write each radical as a multiple of sqrt(2) \[\sqrt{8} = \sqrt{4\times2} = \sqrt{4}\times \sqrt{2} = 2\sqrt{2}\] so \[11\sqrt{8} = 11\times2\sqrt{2} = 22\sqrt{2}\] you need to do the same type of thing for \[6\sqrt{12}\]
not quite.... here is the start \[6\sqrt{12} = 6\sqrt{4 \times3}\] so in your question you will have 2 like terms, (sqrt(2) and one that is sqrt(3)
so at the moment you have \[22\sqrt{2} + 6\sqrt{4\times3} - 5\sqrt{2}\]
okay
then you have \[(22 - 5)\sqrt{2} + 6\sqrt{4\times3}\]
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okay
\[17\sqrt{2} + 6\sqrt{4}\times \sqrt{3}\] I'll let you finish it
well what would i do because there's no like terms?
\[17\sqrt{2} + 12\sqrt{3}\]
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