Just looking to make sure this problem was done correctly. Factor the following polynomial completely: (3x-5)(x-3)-(x-4)(x-3) The answer I got was 2x-26
I wanted to make sure the answer was correct, so if you wanted to double check it that would be awesome.
Yeah, the foil method is what i did.
well, there is a gcf you can factor out without having to multiply it all and then re-factor. Do you see the common factor?
x
if you pull out a (x-3), you get (x-3)[(3x-5)-(x-4)] (x-3)(3x-x-5+4) (x-3)(2x-1)
Here is what i did:\[(3x-5)(x-3)=3x ^{2}-9x-41 (x-4)(x-3)=x ^{2}-7x+12\]
Then subtracted the trinomials.
I know how the foil method works.
@StefaniTriscuit I found your error. -5x - 9x = -14x , not -9. Then, -5 x -3 = 15 , not -41. If you fix that, then you've got it right.
Ah! haha, thank you! so obvious now!
you're welcome!
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