Just looking to make sure this problem was done correctly.
Factor the following polynomial completely:
(3x-5)(x-3)-(x-4)(x-3)
The answer I got was 2x-26
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OpenStudy (anonymous):
I wanted to make sure the answer was correct, so if you wanted to double check it that would be awesome.
OpenStudy (anonymous):
Yeah, the foil method is what i did.
OpenStudy (btaylor):
well, there is a gcf you can factor out without having to multiply it all and then re-factor. Do you see the common factor?
OpenStudy (anonymous):
x
OpenStudy (btaylor):
if you pull out a (x-3), you get
(x-3)[(3x-5)-(x-4)]
(x-3)(3x-x-5+4)
(x-3)(2x-1)
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OpenStudy (anonymous):
Here is what i did:\[(3x-5)(x-3)=3x ^{2}-9x-41 (x-4)(x-3)=x ^{2}-7x+12\]
OpenStudy (anonymous):
Then subtracted the trinomials.
OpenStudy (anonymous):
I know how the foil method works.
OpenStudy (btaylor):
@StefaniTriscuit I found your error. -5x - 9x = -14x , not -9.
Then, -5 x -3 = 15 , not -41. If you fix that, then you've got it right.
OpenStudy (anonymous):
Ah! haha, thank you! so obvious now!
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