Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

If 1200 cm^2 of material is available to make a box with a square base and an open top find the largest possible volume of the box

OpenStudy (anonymous):

What have you been given: Surface area of box: 1200 cm² Volume of box: s²h Where: s = side of square base h = height of box Putting the height of the box in terms of s: You can write the formula for the surface area of the box in terms of s and h like so: S.A. = s² + 4sh, remember it’s open Where: S.A. = surface area or 1200 cm², s² = the square base, and 4sh = the four 'walls' of the box. 1200 = s² + 4sh 1200 - s² = 4sh (1200 - s²)/(4s) = h Substitute h (in terms of s) into the formula for volume. v(s) = s²((1200 - s²)/(4s)) ……….Simplify. v(s) = s(1200 - s²)/4 ………..Expand. v(s) = 300s - (1/4)s^3 To find the largest possible volume of the box, you find the maximum value of this function. Take the derivative of the volume function using the Power Theorem. v'(s) = 300 - (3/4)s² Zeroes of the v' function will give you the x values that correspond to local extreme in the v function. 0 = 300 - (3/4)s² Solve for zeroes. -300 = (-3/4)s² 400 = s² Your two possible values for s are -20 and 20. Take the second derivative to see if the s values will give you a local maximum or minimum. v"(s) = -(3/2)s If v" is negative at s then v is concave down at s, indicating a local maximum. If v" is positive at s then v is concave up at s, indicating a local minimum. v"(-20) = -(3/2)(-20) v"(-20) = 30 This indicates a local minimum for v at s, not what we are looking for. v"(20) = -(3/2)(20) v"(20) = -30 This indicates a local maximum for v at s, which is what we are looking for, the maximum volume of the box. This makes sense because if you remember what we assigned the variable s to, a side length, side lengths cannot be negative. Once we have found the value for s, we can substitute it into the function we created for the volume of the box. v(s) = 300s - (1/4)s^3 v(s) = 300(20) - (1/4)(20)^3 v(s) = 6000 - (1/4)(8000) v = 6000 - 2000 The largest possible volume of the box is 4000 cubic centimeters.

OpenStudy (anonymous):

Thank you! I was confused when it came to the second derivative part. It now makes a ton more sense.

OpenStudy (anonymous):

you welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!