Did I go this Algebra problem correctly?

Question

anonymous · Answer

Simplify, Assume that no denominator is equal to zero.

anonymous · Answer

(2a^4b)^2/16b^5

anonymous · Answer

I said it was a^8/8b^3, correct?

lgbasallote · Answer

$$\huge \frac{(2a^4 b)^2}{16b^5} \implies \frac{4a^8b^2}{16b^5} $$
from what i have just written i can already say you were wrong...

lgbasallote · Answer

you were close though...and that counts for something

anonymous · Answer

May I perhaps see the full answer, please?

lgbasallote · Answer

what do you mean?

anonymous · Answer

What's the answer, then?

anonymous · Answer

I have to know where I went wrong in order to improve myself.

anonymous · Answer

I guess I have to see it be done again and see the answer.

What is the answer?

anonymous · Answer

Hello?

anonymous · Answer

...You should learn to do simple algebra on your own. It is a very useful skill. The answer is 

$$a^{8}/4b^{3}$$

anonymous · Answer

That's the intention of this. Here is my logic: 16, divided by 2 is 8. Therefore, 8 must be in the denominator. Now, may you please tell me where I went wrong?

lgbasallote · Answer

look at the thing i posted so you can see where you went wrong

lgbasallote · Answer

i assume you forgot to SQUARE 2 as well

anonymous · Answer

^What he/she said^

lgbasallote · Answer

you did $$\frac{2}{16}$$ when you should have done $$\frac{4}{16}$$

anonymous · Answer

Ah. Thank you.