Question

The vapour density of partially dissociated iodine at a certain temperature was found to be 80. What is its degree of dissociation?

Answer 1

do you got any formulas to work with?

Answer 2

No idea

Answer 3

yea i'm sorry i don't think i will be able to help with this one

Answer 4

Can u call some one else

Answer 5

.587?

Answer 6

yes u r correct @Ishaan94

Answer 7

@Ishaan94 hw do u get it

Answer 8

Vapor density of dissociation vapor = 127.

Let x be the degree of dissociation.

80/120 = 1/(1+x) => x = .587

I hope you can get the equation and number moles at equilibrium.