The number 2012 x 2013 x 2014 + 2013 is the cubed of: A) 2012 B) 2013 C) 2014 D) 2112 E) 2113
actually it's (2013 x 2012 x 2014) + 1
solve that...then get the cube root to get your answer
\[\huge \sqrt[3]{2012 \times 2013 \times 2014 + 1} = \text{answer}\] any questions?
Is the answer 2013? @lgbasallote
wait...let me check in wolfram
And yeah I'll put up more questions that I don't understand (:
i meant follow up qustion lol...anyway wolfram gave me 2012.99
so yeah i guess it can be rounded off to 2013
limited precision arithmetic
Oh my bad and okayy thanks again
welcome welcome
2013
(2012 2013 2014+2013)^(1/3)
But is there a faster way to do it without using a calculator
....manual? o.O
Yeah
...i do not think so....
this is the fastermethod http://www.wolframalpha.com/input/?i=cube+root+of+%282012+x+2013+x+2014+%2B+2013%29
Because I spent a long time multiplying the numbers and curbing some of the answers
2012 x 2013 x 2014 + 2013 (2013-1) x 2013 x (2013+1) + 2013 2013 [ 2013^2 - 1^2 + 1] 2013^3
but i can approximate it to be 2013 because it's 2012*2013*2014 2013 is like the middle...and it's multiplication....so it's like 2013*2013*2013 does that make sense? lol
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