Question

HELP!! solve sin^-1(√2/2) + cos^-1x = 2pi/3....do you start with solving by cos^-1x ?

Answer 1

si the first step correct>

Answer 2

i would start by knowing that \(\sin^{-1}(\frac{\sqrt{2}}{2})=\frac{\pi}{4}\)

Answer 3

so start with
\[\frac{\pi}{4}+\cos^{-1}(x)=\frac{2\pi}{3}\]
then subtract \(\frac{\pi}{4}\) from both sides

Answer 4

okay

Answer 5

wait why is it pi/4?

Answer 6

oh sin45 is pi/4 okay

Answer 7

\(\sin^{-1}(\frac{\sqrt{2}}{2})=\frac{\pi}{4}\) because \(\sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}\)

Answer 8

ignore degrees. you are clearly working in radians (numbers) because you have \(\frac{2\pi}{3}\)on the right

Answer 9

the sine of 45 degrees is not \(\frac{\pi}{4}\)! if you measure an angle in degrees, then you could say \(\sin(45)=\frac{\sqrt{2}}{2}\)

Answer 10

okay. so i got up to here!

Answer 11

pi/4 lies on 45 degrees i mean....is that correct?

Answer 12

@satellite73

Answer 13

hello???

Answer 14

too much work

Answer 15

\[\frac{2\pi}{3}-\frac{\pi}{4}=\frac{5\pi}{12}\]

Answer 16

oh i see, no not too much work !

Answer 17

yes, you have it, i was thinking wrong

Answer 18

last job is to plug in the numbers in what you wrote above and you will be done

Answer 19

okay thank you!!

Answer 20

yw