Question

4.) Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form.

Answer 1

What is the slope of the line perpendicular to y = 4x + 7?

Answer 2

4

Answer 3

That's the slope of the given line.
What's the slope of the line perpendicular?

Answer 4

id start out with a parallel line, then just trick out the slope

Answer 5

Find that slope then do (y - -3 / x - 2) = m

Answer 6

how do i find that slope?

Answer 7

The rule is the perpendicular is the negative inverse
First slope = 4
Second slope = - 1/4

Answer 8

the material that is in the chapter before this questions gives you properties regarding perp slopes i beileve :/

Answer 9

Okay.

Answer 10

" (y - -3 / x - 2) = m "

this seems a bit odd to me

Answer 11

i see it now, its just the point slope form reaaranged

Answer 12

i dont get what the slope is though :(

Answer 13

when given a slope: a/b
the perp slope is simply the flip negation of it: -b/a

Answer 14

you say correctly that the slope given is 4, lets say 4/1

can you show me the perp slope from that?

Answer 15

whats a perp slope??

Answer 16

in the context of the question at hand, i would say that perp slope is shorthand for perpendicular slope

Answer 17

mathikers hate to write :)

Answer 18

here is a fairly simple method
step 1, write out the given equation

y = 4x + 7

ignore the constant, we are going to have to resolve for it

y = 4x + b

perp the slope

y = (-1/4)x + b

this is almost done now.

plug in the values of x and y from the given point (2,-3) to solve for b

-3 = (-1/4)2 + b

-3 = -1/2 + b

-3 + 1/2 = b

(-6 + 1)/2 = b

-5/2 = b

plug in the value of b back into the equation

y = (-1/4)x - 5/2

and voila

Answer 19

thats not all step 1.... i just forgot to write in "step ... " for the others lol

Answer 20

it makes so much sense now! and ok lol. thank you very!!!!!!!!!!!!

Answer 21

the term "standard form" youll have to google; it might be what we did, or it might mean:

ax + by = c format, i cant recall

Answer 22

your correct!

Answer 23

yay!! staving off althiemers for one more day :)

Answer 24

lol thanks again (: