Question

factorize : \[\large{x^2+(a+b+c)x+ab+bc}\]

Answer 1

I did like this :
\[\large{x^2+ax+bx+cx+ab+ac}\]
\[\large{x^2+bx+cx+ax+ab+ac}\]
\[\large{x(x+b+c)+a(x+b+c)}\]
\[\large{(x+a)(x+b+c)}\]

Answer 2

Good..

Answer 3

Its absolutely correct.........

Answer 4

but the book shows answer as :
\[\large{(x+b)(x+a+c)}\]
which is wrong

Answer 5

so book is wrong?

Answer 6

well its easy to check just simplify the book's answer

Answer 7

How can @mathslover be wrong..

Misprint will be in book..

Answer 8

Yes the book has factorised.
\[x^2 + (a+b+c) x + ab + bc\]

Answer 9

yes it is right also :
\[\large{(x+b)(x+a+c)}\]
\[\large{x^2+ax+cx+bx+ab+cb}\]
\[\large{x^2+x(a+b+c)+ab+bc}\]

Answer 10

\[\large{(x+a)(x+b+c)}\]
\[\large{x^2+bx+cx+ax+ab+ac}\]
even i am wrong

Answer 11

oh sorry i wrote the question wrong it was bc

Answer 12

No how you got cb in last ??

Answer 13

You are not wrong...........
This is what the question is ...... ?

Answer 14

@mathslover you have done a mistake in reading question..

Answer 15

:D

That's what I used to do.........

Answer 16

There is bc in the last and not ac as you had written earlier..

Answer 17

sorry for the mistake : so here i go with the correct one:
\[\large{x^2+(a+b+c)x+ab+bc}\]
\[\large{x^2+ax+bx+cx+ab+bc}\]
\[\large{x^2+ax+cx+ab+bc+bx}\]
\[\large{x(x+a+c)+b(x+a+c)}\]
\[\large{(x+b)(x+a+c)}\]

Answer 18

so it is right now?

Answer 19

Very nice

Answer 20

Well Done..

Answer 21

thanks every one ..

Answer 22

sorry for mistake