What are the zeros of the polynomial function: f(x) = x3 + 2x2 – 24x ?

–6, 0, 4

6, 0, –4

–6, 0, –4

6, 0, 4

Question

What are the zeros of the polynomial function: f(x) = x3 + 2x2 – 24x ?

 –6, 0, 4

 6, 0, –4

 –6, 0, –4

 6, 0, 4

anonymous · Answer

you have the choices given so you can check to see what works 
that is, replace $x$ by -6, 4, 6,-4 and see what gets you zero

parthkohli · Answer

Hint: $$x^3 + 2x^2 - 24x = x(x^2 + 2x - 24)$$

anonymous · Answer

okay

anonymous · Answer

on the other hand, if you do not feel like doing so much work, you can also cheat http://www.wolframalpha.com/input/?i=x3+%2B+2x2+%E2%80%93+24x+%3D0

parthkohli · Answer

You may even do it something like$$x(x^2 + 2x - 24) = 0 \Longrightarrow x = 0, x^2 + 2x - 24 = 0 $$

parthkohli · Answer

Zero is certainly a solution.
Find the solutions to $x^2 + 2x - 24 = 0$.

anonymous · Answer

The answer is A (0,-6, and 4). You have to set the equation equal to zero:
x3+2x2-24x=0
x(x2+2x-24)=0
x(x+6)(x-4)=0
x=0 x+6=0 x-4=0
x=0 x=-6 x=4

anonymous · Answer

To all those taking this, the answer is  NOT -6,0,4. Just took the test.

anonymous · Answer

it is 6 0 4 i took the test and it as right for FLVS students