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Mathematics 11 Online
OpenStudy (aravindg):

Is this identity valid ?

OpenStudy (aravindg):

\[\large \tan^{-1}x+\tan^{-1}y+\tan^{-1}z=\tan^{-1}\frac{x+y+z-xyz}{1-xy-yz-zx}\]

OpenStudy (aravindg):

@UnkleRhaukus , @.Sam. , @Callisto

OpenStudy (anonymous):

let x=y=z=1

OpenStudy (aravindg):

so?

OpenStudy (anonymous):

lol.....im wrong...nothing.......lets think again

OpenStudy (aravindg):

@amistre64 , @experimentX

OpenStudy (experimentx):

no that's the right trick ... test for few arbitrary values.

OpenStudy (experimentx):

that's how i validate things ... before doing it if it looks ugly.

OpenStudy (aravindg):

i jst got to this eqn by myseslf ... so i dont knw ifthis can be generalised for all x,y,q

OpenStudy (aravindg):

i didnt see such an identituy in any textbook, i only saw tan-1 x+tan-1 y

OpenStudy (aravindg):

can anyone tell me if this is valid for all x,y ,z?

OpenStudy (anonymous):

is this correct?\[\tan^{-1}x +\tan^{-1}y=\tan^{-1}\frac{x+y}{1-xy} \]

OpenStudy (aravindg):

yep

OpenStudy (aravindg):

thats why i thought of an analogous for 3x :P

OpenStudy (aravindg):

i mean x,y ,z

OpenStudy (anonymous):

is this correct?\[\tan^{-1}x +\tan^{-1}y+\tan^{-1}z=\tan^{-1}\frac{x+y}{1-xy}+\tan^{-1}z\\=\tan^{-1}\frac{z+\frac{x+y}{1-xy}}{1-z\frac{x+y}{1-xy}}=\tan^{-1}\frac{x+y+z-xyz}{1-xy-xz-zy}\] so its valid

OpenStudy (anonymous):

lol.....ignore' is this correct?'

OpenStudy (experimentx):

lol .. that's correct!!

OpenStudy (aravindg):

:P thx a lot!!!!!!!!!!!!!!!!!!!111

OpenStudy (anonymous):

yw :)

OpenStudy (anonymous):

Just remember that it is not valid for x belonging to R due to the domain range conditions you may need to add subtract pi. Otherwise its fine.

OpenStudy (anonymous):

@AravindG

OpenStudy (aravindg):

k thx

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