using de-moivre formula solve (2+4i)^2 help , i really have no idea
As far as I am concerned, de-moivre is applied to complex numbers in polar coordinate form, so you might want to get the above number first into it's complex form.
the above number into it's complex polar coordinate form*
first convert it into polar or trigonometrical form without squaring then apply this \[\LARGE{(\cos \theta + i \sin \theta)^n=\cos n \theta + i \sin n \theta.}\]
sorry @greysica \[\LARGE{(|z|\cos \theta + i |z|\sin \theta)^n=|z|(\cos n \theta + i \sin n \theta).}\]
okay , what should I do ?
Again sorry!! @greysica \[\LARGE{(|z|\cos \theta + i |z|\sin \theta)^n=|z|^n(\cos n \theta + i \sin n \theta).}\]
i know i know that's the formula , I mean how I do the calculation with that formula ?
oh !!!!!!! well u must forget square first then put the value of |z|; \[|z|=\sqrt{x^2+y^2}.\]& theta \[\theta = \tan^{-1}\frac{y}{x}\]in ur polar form if ur z = x+iy. ok! u will get then\[|z|(\cos \theta + i \sin \theta)\] now square it k! & apply de moivre:) as u know the formula.
i dont get it :( can u do calculation for me ?
Do the formulas above make sense to you @greysica, because they should before you apply them. De-Moivre's law works for polar coordinates, and to get an equation into polar coordinate it has to remain an unique identity, you require two things for that: 1. The distance from the origin which is given by Pythagoras' theorem. 2. The angle between x-axis and the line which is given by the inverse tan function (trigonometry)
So you are just solving for values to plug into the equation, the formula itself will then translate your values again into rectangular coordinates. You can double check in the end, because it's just a binomial.
can u give me an example ?
anyone help ? @phi ?
|dw:1343926057398:dw| change to polar coordinates using pythagoras to find the magnitude and tangent to find the angle
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