Question

Please see attachment for question ..

Answer 1

this is what i tried ..

Answer 2

@asnaseer @Callisto

Answer 3

@mukushla

Answer 4

@eliassaab

Answer 5

u did it well my friend and u got

\[(a+b+c)\frac{1+k^2}{1+k} \ \ (\star)\]

use this to complete ur proof

when u have\[\frac{x}{a}=\frac{y}{b}=\frac{z}{c}=k\] u can write \[\frac{x+y+z}{a+b+c}=k\]put this in the \((\star)\)

Answer 6

so i shall put k =(x+y+z)/(a+b+c) .. right?

Answer 7

yeah...

Answer 8

ok .. i got it .. thanks a lot @mukushla

Answer 9

i was nt able to put here the work due to some error sorry ..

but yes i got it finally

Answer 10

yw ...... :)

Answer 11

well i did right partially but after that was diverted thanks .

well was componendo and dividendo applied by you there?