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Mathematics 16 Online
OpenStudy (anonymous):

solve the quadratic equation!! 10x^2 – 7x – 12 = 0

OpenStudy (anonymous):

help @qpHalcy0n ??

OpenStudy (neo92):

I think u mean solve for x. If so u can use the quadratic formulae \[x=(-b\pm\sqrt{b^{2}-4ac})/2a\]

OpenStudy (anonymous):

No need to solve for x

OpenStudy (anonymous):

But this can be factored.

OpenStudy (anonymous):

how??

OpenStudy (anonymous):

Possible factors for 10 are 1 and 10 or 2 and 5 So set up two possible solutions based on these two. OK?

OpenStudy (anonymous):

We'll follow the branch that works out (5x ) (2x ) Now we need factors for 12.

OpenStudy (anonymous):

4 and 3

OpenStudy (anonymous):

6 and2

OpenStudy (anonymous):

Start with 3 and 4, if it doesn't work, move to 6 and 2, then 12 and 1. OK?

OpenStudy (anonymous):

(5x 3 or 4) (2x 3 or 4) Now.. Notice the signs. we have -7x - 12

OpenStudy (anonymous):

So either 3 is positive and 4 is negative, or the reverse. OK?

OpenStudy (anonymous):

yess!!

OpenStudy (anonymous):

Can you do it now?

OpenStudy (anonymous):

so it would be (5x+3) (2x-4)

OpenStudy (anonymous):

I get -14x with that one

OpenStudy (anonymous):

where do you get -14??

OpenStudy (anonymous):

3 times 2x - 4 times 5x

OpenStudy (anonymous):

multiply it out but you're very close

OpenStudy (anonymous):

do i flip the numbers

OpenStudy (anonymous):

You'll only know if you multiply it out and it's correct (5x + 4) (2x - 3) ??

OpenStudy (anonymous):

this is right right???

OpenStudy (anonymous):

@telliott99 ??

OpenStudy (anonymous):

you can do this, can't you?

OpenStudy (anonymous):

nooo thats why im geetting help smh

OpenStudy (anonymous):

(px + q)(rx + s) = prx^2 + psx + qrx + qs

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