Mathematics
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OpenStudy (anonymous):
solve the quadratic equation!! 10x^2 – 7x – 12 = 0
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OpenStudy (anonymous):
help @qpHalcy0n ??
OpenStudy (neo92):
I think u mean solve for x.
If so u can use the quadratic formulae \[x=(-b\pm\sqrt{b^{2}-4ac})/2a\]
OpenStudy (anonymous):
No need to solve for x
OpenStudy (anonymous):
But this can be factored.
OpenStudy (anonymous):
how??
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OpenStudy (anonymous):
Possible factors for 10 are 1 and 10 or 2 and 5
So set up two possible solutions based on these two. OK?
OpenStudy (anonymous):
We'll follow the branch that works out
(5x ) (2x )
Now we need factors for 12.
OpenStudy (anonymous):
4 and 3
OpenStudy (anonymous):
6 and2
OpenStudy (anonymous):
Start with 3 and 4, if it doesn't work, move to 6 and 2, then 12 and 1. OK?
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OpenStudy (anonymous):
(5x 3 or 4) (2x 3 or 4)
Now.. Notice the signs. we have -7x - 12
OpenStudy (anonymous):
So either 3 is positive and 4 is negative, or the reverse. OK?
OpenStudy (anonymous):
yess!!
OpenStudy (anonymous):
Can you do it now?
OpenStudy (anonymous):
so it would be (5x+3) (2x-4)
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OpenStudy (anonymous):
I get -14x with that one
OpenStudy (anonymous):
where do you get -14??
OpenStudy (anonymous):
3 times 2x - 4 times 5x
OpenStudy (anonymous):
multiply it out
but
you're very close
OpenStudy (anonymous):
do i flip the numbers
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OpenStudy (anonymous):
You'll only know if you multiply it out and it's correct
(5x + 4) (2x - 3)
??
OpenStudy (anonymous):
this is right right???
OpenStudy (anonymous):
@telliott99 ??
OpenStudy (anonymous):
you can do this, can't you?
OpenStudy (anonymous):
nooo thats why im geetting help smh
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OpenStudy (anonymous):
(px + q)(rx + s) = prx^2 + psx + qrx + qs