Hey guys can I get some help?! I need step by step instruction when evaluating sin(Cos^-1(4/5)+Tan^1(3/4)). What is an identity used in the solution? a. sin ( x + y) = sin x cos y - cos x sin y b. sin ( x + y) = cos x cos y + sin x sin y c. sin ( x + y) = sin x cos y + cos x sin y d. sin ( x + y) = cos x cos y - sin x sin y
\(\cos^{-1}(\frac{4}{5}) + \tan^{-1}(\frac{3}{4})\) Is that right?
Yes, that's right
@Hero
I'm stumped.
sin(Cos^-1(4/5)+Tan^1(3/4)) I think you forgot the sin in front
:(
Identity that will be used in this solution will be the first one i.e. A
sorry my Bad you have to go for third Identity i.e. C
Oh, can you please show me how you got that??
you know that formula for Identity Sin(A+B) = CosA*SinB+SinA*CosB
Can i give an idea here if you guys don't mind
then we have to use the same formula @godorovg go ahead
Oh O.K. Yes please do @godorovg
we know sin/cos = tan is right/ so why want sub in and slove in this manner
and work backwards just a thought
like this tan a-b/ cos a-b =sin a-b /2/sin a-b2 =sin a-b /ctn C/2 and so on
thoughts here
Oh ok. And that gives us c. as well?
@godorovg
yes it should if done right
Thank you for your input!
does that make sense to you??
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