Question

please
write expression in a+bi?
6+2i/9-3i

Answer 1

To simplify it multiply top and bottom by the conjugate of the bottom ... so by 9 + 3i:

= [(6 + 2i)(9 + 3i)] / [(9 - 3i)(9 + 3i)]

= [54 + 18i + 18i + 6i²] / [9² - 9i²]

= [54 + 36i - 6] / [81 + 9] ... [b/c i² = -1]

= [48 + 36i] / 90

= (48/90) + (36i / 90)

= (8/15) + (6/15)i

= (8/15) + (2/5)i

Answer 2

conjugate formula?