Question

solve the quadratic equation x2 – 14x + 40 = 0

Answer 1

factor \[x^2-14x+40\]

Answer 2

do you know how to factor? :)

Answer 3

nooo

Answer 4

okay well ill show you :)

Answer 5

Khans are best at factoring:
http://www.youtube.com/watch?v=X7B_tH4O-_s

Answer 6

THis will help you learn in no time:
http://www.khanacademy.org/math/algebra/quadtratics/v/solving-quadratic-equations-by-factoring-avi

Answer 7

so we're looking for two binomials that, when multiplied, equal the trinomial x^2-14x+40

so first we need to find two numbers that multiply to give us the coefficient of the first term and add to give us the coefficient of the second term:
\[-4 \times-10=40\]\[-4-10=-14\]
so we use these two numbers, -4 and -10, and create two binomials:
\[(x-4)(x-10)\]

now that you've factored you have \[(x-4)(x-10)=0\]so we set those two binomials to zero and solve for x\[x-4=0~~\rightarrow~~x=4\]\[x-10=0~~\rightarrow~~x=10\]
so your two solutions are:\[x=4~~or~~x=10\]

Answer 8

Thanks so much

Answer 9

your welcome :)