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What is the solution to the equation log4 x + log4 2=3
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\[\log_{4}x +\log_{4}2 =3 \] is that the question?
Use this property:\[\log_a b + \log_a c \to \log_a(b*c)\]
yes
\[\log_{4}x +\log_{4}2 = \log_{4}64 \] \[\log_{4}(2x) =\log_{4}64 \] now ignore the logs and you get: 2x=64 x=??
how did you get the 64?
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OK, first of all we dealing with logs, so the 3 on the right hand side is and exponent of base 4, and since we want both sides to have logs to base 4, then we need the actual number which is 4^3 =64, got it?
ohh ok, I get it! thanks
you welcome
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