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simplify the trigonometric expression
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\[2+\tan^2x \over \sec^2x\] all -1 (how do you put -1 on the same line as the fraction?) Should i convert the tan using the pythagorean identity and convert both sec using the reciprocal?
Hint: relation between tan and sec.
i get to sec^2(x)+1-sec^2(x).. is there a good step by step trigonometric expression solver online? I'm having trouble on these.
Alright, if it is -((2+tan^2x)/)sec^2x)) then that simplifies (by sec-tan relation, which is sec^2x=tan^2x+1) to -((1+sec^2x)/(sec^2x))=-1/sec^2x -1
That equals -cos^2x-1
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*-cos^2(x)-1
Which simplifies to sin^2(x)-2
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