Helpp! 1) Give two examples of how greatest factors are used in Algebra 1. 2) Why are even and odd exponents significant when simplifying square root radical expressions? 3) Explain how combining like terms and combining radicals is similar. 4) Simplify (x^2+8x)/(x^2+10x+16) 5) Simplify (7x^2)/sqrt(x^5)
1) Greatest factors can help simplify a problem: (2x + 10)/4 the greatest common factor is 2, so lets factor that out: 2(x+10)/4 = (x + 10)/2 2) Even and odd exponents will determine how man roots you have when simplifying square roots. Even exponents will always give you a positive and negative root, and odd expressions will only give you either a positive OR negative root.
Can you do number 4 and 5 and show your work so i know how to do it?
4 is x/x+2
Can you show your work please?
thank you @Hermeezey
5 is 7sqrt(x) / x
@Snapbacklive can you please show your work?
Ok To start, you have to move the sq root(x^5) out of the denominator. To do that, you have to multiply the fraction by sqrt(x^5)/sqrt(x^5). You do this, because it's the same as multiply it by one. You're problem would look like this: 7x^2 / sqrt(x^5) * (sqrt(x^5)/sqrt(x^5)) ---> 7x^2 * sqrt(x^5) / x^5 Now you square root the x^5 on the top by square rooting x^4 out of the x^5, leaving x in the sqrt. It looks like this: 7x^4 * sqrt(x) / x^5 You're almost done. Now that you've done all this, the the x^4 on top and the x^5 on the bottom can cancel out, so there is only x on the bottom, like so: ANSWER: 7*sqrt(x) / x
4) (x^2 + 8x) / (x^ + 10x + 16) first we should factor out the (x) in the top, since we can't do anything else with it: x(x+8)/ (x^2+10x+16) Now looking at the bottom, what two numbers give you 10 when added together and 16 when multiplied? Well, to me, it looks like 2 and 8 and I am pretty sure you would agree. So lets break up the bottom into the roots: x(x+8)/(x+2)(x+8) Now we see a (x+8) in both the top and the bottom, we we can go ahead and cancel them out: x/(x+2) That should be your final answer.
@Snapbacklive i got the answer 7sqrt(x^5)/x^3? Am i wrong? @Hermeezey Thank you!
Yes, i got the same answer until someone so howd me how to do it.
Okay
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