Question

find the derivative of f(x)=1/x(x+1)

Answer 1

\[f(x) = \frac{1}{x(x+1)}\]
is that the question?

Answer 2

are you familiar with partial fractions?

Answer 3

that is the question

Answer 4

@lgbasallote just do (1/v)'

Answer 5

if mariaad knows partial fractions it would be easier...

Answer 6

i got -2x-1/(x^2)(x+1)^2

Answer 7

x^2(x+1)^2 as the denom

Answer 8

im thinking the denominator is wrong..

Answer 9

you should put it as \[\frac{1}{x^2 + x}\]
then you can do the derivatives

Answer 10

so what is the denominator

Answer 11

it would be \[\frac{ -(2x +1)}{(x^2+x)^2} \implies - \frac{2x - 1}{(x^2+x)^2}\]

Answer 12

sorry i need it for an online homework that is due at midnight

Answer 13

so the denominator is your only mistake

Answer 14

-2x - 1/((x2) + x)2.

Answer 15

when i plug that in it says it is wrong

Answer 16

right

Answer 17

hmm?

Answer 18

try expanding the denominator?

Answer 19

nothing is working ! ahh

Answer 20

hmm wait....it seems you were right the first time haha sorry

Answer 21

but i dont think i was wrong....guess they just prefer it written the way you did..

Answer 22

well either way when i type in that answer it says it is wrong i was wondering if maybe theres another way to write it maybe the parentheses are wrong or something

Answer 23

you can write it the way you did before \[\frac{-2x-1}{x^2(x+1)^2}\]

Answer 24

thye're just equal

Answer 25

i know that I am saying that when I type it into the program it cant have the exponent like that it has to be x^2 for example so when i attempted to put that in the form it says it is wrong ...i cant figure out how else to write it