Question

Hey I just met u and this is crazy ..
Here my problems , Help me maybe ? :))
prove approximation of Mac Laurin Polinom from this function

Answer 1

No.

Answer 2

okay .. :(

Answer 3

Harsh. @lgbasallote

Answer 4

haha lol

Answer 5

So help her already. I dont know what that is, lol. Can you atleast try? @lgbasallote

Answer 6

i have no idea

Answer 7

yeah yeah , at least try if u can .. :)

Answer 8

I'm not sure what you mean, you want to derive the three series expansions above?

Answer 9

@greysica do I understand that you just want to see how the above statements are derived?

Answer 10

I have to find the way how it works as a function based on mac laurin polinom

Answer 11

I can derive the mcLauren series from the function, but that doesn't sound like what you want.

Answer 12

hmm , I'm not sure actually about question for my homework , but would u like show me how it works based on ur opinion ?

Answer 13

the Taylor expansion of a function about x=0 is\[f(x)=\sum_{n=0}^\infty{f^{(n)}(0)\over n!}x^n\]where \(f^{(n)}(0)\) is the \(n^{th}\) derivative of the function at x=0

Answer 14

is that for A ?

Answer 15

@greysica what Turing Test has mentioned above is general formula for Taylor series about a=0 also Known as Maclaurin series.

Answer 16

@greysica you need Maclaurin Polynomials of the given functions??

Answer 17

ya :)

Answer 18

ok @greysica you there?
I'll walk you though it must you must participate
the formula for the series expansion of a function about \(x=0\) is\[f(x)=\sum_{n=0}^\infty{f^{(n)}(0)\over n!}x^n\]where \(f^{(n)}(0)\) is the \(n^{th}\) derivative of \(f(x)\) at the value \(x=0\)

so let's start with the first function, \(f(x)=a^x\)
what is the first term of the sequence according to the formula?
i.e. when \(n=0\)

Answer 19

x=0 ?

Answer 20

not not x=0