solve 6/(x-4)>-5/3
\(\large\frac{6}{x-4} > -\frac{5}{3}\)
Hint: Cross Multiply to get: 6(3) > -5(x-4)
yeah, I got x>2/5. but i was wondering what i should do if x was negative...i tried to just flip the sign but it wasnt an answer choice on my assignment
If you did the steps correctly, you would end up with -2 > -5x At this point, what you want to do is add 5x to both sides, while also adding 2 to both sides to get: 5x > 2 Then you could simply divide both sides by 5 to get: x > 2/5 This is usually the case that students normally have trouble with, but I just showed you how to avoid the trouble.
but (2/5, inifinity) isnt the entire solution...so i was wondering if you had to consider 2 different situations in this equation?
(sorry for the hassle, inequalities are very confusing to me)
\((2/5, 4) (4, \infty)\) since \(x \ne 4\)
With inequalities of this type, you have to pay attention to the denominators of fractions, because the denominators of fractions can never equal zero. Good catch.
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