Question

Find the heat that flows in 1 s through a lead brick 15 cm long if the temperature difference between the ends of the brick is 8.8° C. The cross-sectional area of the brick is 14 cm2.

Answer 1

rate of heat flow = (thermal conductivity of lead * cross-sectional area * temp. difference)/ lenght of brick
\[\Delta Q/\Delta t= (\kappa \times \Delta T \times A) \div L\]
thermal conductivity of lead=35.3 W·m^−1·K^−1