What is the phase shift for this graph? http://www.wolframalpha.com/input/?i=y%3Dsin%28x%2Bpi%2F3%29

Question

anonymous · Answer

a. pi/3 to the left
b. 2pi/3 to the right
c. pi/3 to the right
d. 2pi/3 to the left

hero · Answer

There's a formula for these you're supposed to remember

anonymous · Answer

:/ May you refresh my memory?

hero · Answer

For this one it would be

$y = a\sin(bx-c) + d$

hero · Answer

a = amplitude
b = factor of x
c = horizontal shift
d = vertical shift
c/b = phase shift

anonymous · Answer

true enough
this really has nothing to do with trigonometry
compared the the graph of $y=f(x)$ the graph of $y=f(x+\frac{\pi}{3})$ is moved $\frac{\pi}{3}$ units to the left

anonymous · Answer

So pi/3 units to the left, correct?

hero · Answer

Well considering that in this case, b = 1, which means $\large\frac{c}{b}= c \div b=\frac{pi}{3} \div 1$ = $\frac{\pi}{3} \times 1 = \frac{\pi}{3}$

anonymous · Answer

yes

anonymous · Answer

Thank you both! Wish I could give more than one medal :/