Question

Please help! I need to find a solution :/ Click attached

Answer 1

i would simply plugin options and check

Answer 2

1) 0
3sin^2x + 2sinx
3(0) + 2(0)
=0
\(\ne RHS\)

Answer 3

2) 90
3sin^2x + 2sinx
3(1) + 2(1)
= 5
\(\ne RHS\)

Answer 4

3) 270
3sin^2x + 2sinx
3(1) + 2(-1)
= 1
\(= RHS \huge \checkmark\)

Answer 5

Let sin x = y

Answer 6

Thank you @ganeshie8 for showing me step by step!

Answer 7

Then:

3y^2 + 2y = 1

Answer 8

This is the alternate version

Answer 9

... actually mine is a brute-force way... we had to check every option. good is by solving

Answer 10

@Hero thank you for sharing the alternative :)

Answer 11

3y^2 + 2y - 1 = 0
3y^2 + 3y - 1y - 1 = 0
3y(y+1)-1(y+1) = 0
(y+1)(3y-1) = 0

y + 1 = 0
3y - 1 = 0

sin x + 1 = 0
3sin x - 1 = 0

sin x = -1
sin x = 1/3

x = sin^(-1)(-1)
x = sin^(-1)(1/3)

Answer 12

Thanks Hero!

Answer 13

yw Charlie :P