Question

Carbon dioxide in a soft drink with an initial mass of \(381.04\)g was carefully extracted and collected as a gas. The drink final mass was \(380.41\)g.

What would be the volume that the Carbon Diodixide occupy at \(100\)kPa and 25 degrees celsius?

Answer 1

Anyone able to give me a hint? what formula do i use?

I haven't done these in a long time..

Answer 2

ok so you have mass of the co2 dont you?
you can do this two ways, one assumes that conditions (temperature and pressure) are ideal or near ideal so you calculate from:
n=m/M
n=V/Vm -> V = n*Vm
or the other way is to calculate the conditions in and use:
pV=nRT -> V = nRT/p
where again
n=m/M

Answer 3

Im not getting it
\[n=\frac{m}{M} => n = \frac{381.04}{268} = 1.4217\]
\[n=\frac{V}{V_{m}} => 1.4217 = \frac{380.41}{V} => V = 267..\]
where did i go wrong?

Answer 4

381,04-380,41 is the mass!