Question

In the given figure , AD is the bisector of \(\angle A\) of \(\triangle ABC\) , then

A) AB > BD

B) AB = BC

C) AB < BD

D) AB = 2BD

Answer 1

@mukushla

Answer 2

ok ..

Answer 3

\[\angle 3 = \angle B +\angle 1\]
\[\large{\angle 3 > \angle B}\] are the steps like this?

Answer 4

@ParthKohli how will it bisect the base

Answer 5

hmn no problem ..

Answer 6

\[\large{\angle 4 = \angle 2+\angle C}\]
\[\large{\angle 4>\angle C}\]

or : \[\large{\angle 3 > \angle B}\]
and \[\large{\angle 4 >\angle C}\]

Answer 7

.....question is wrong?

Answer 8

lets work on that...

Answer 9

agreed with @mukushla

Answer 10

ok @mukushla

Answer 11

@mukushla not given that angle ADB = 90 degree

Answer 12

and how is that isosceles ?

Answer 13

ok.. but that angle is not 90 degree

Answer 14

oh k ..

Answer 15

oh...wait...i think i made a mistake..

Answer 16

here we need to choose the option that is true always...

Answer 17

sorry @mathsolver ....

\[\large\angle 4 = \angle A_2 +\angle 3\]
\[\large{\angle 4 > \angle A_2}\] \[\large{\angle A_1 = \angle A_2}\] so \[\large{\angle 4 > \angle A_1}\]
and \(AB>BD\) always is true

Answer 18

thanks i got it .. :)