find dy/dx if lnx-lny^2+sinxy=8

Question

amistre64 · Answer

what is the derivative of ln(x) ?

amistre64 · Answer

and then of:  -lny^2

and of sin(xy)

and lastly of 8

anonymous · Answer

can i send the wolfram ans

anonymous · Answer

for this question

lgbasallote · Answer

why?

anonymous · Answer

for clearifying

anonymous · Answer

I had trouble with the last term, but found an answer here: http://www.scienceforums.net/topic/23152-implicit-diff/

anonymous · Answer

http://www.wolframalpha.com/input/?i=lnx-lny%5E2%2Bsinxy%3D8+find+dy%2Fdx+

amistre64 · Answer

the last term?  really?  8' = 0

anonymous · Answer

second to last  :)

lgbasallote · Answer

clarifying what? there wasnt even anything that needed to be clarified yet...

anonymous · Answer

this question but i think the ans is wrong in wolfram

amistre64 · Answer

sin(xy); use chain rule

cos(xy) * (xy)'  ; use product rule

cos(xy) * (x'y + xy')  ; since dx/dx=x' = 1, ignore the x's

cos(xy)(y+xy')

anonymous · Answer

@ParthKohli

lgbasallote · Answer

usually askers appreciate being guided and taught rather than being given an answer @best.shakir :)

anonymous · Answer

i also have doubt in this question

anonymous · Answer

@amistre64 thank u

amistre64 · Answer

yalls welcome :)

anonymous · Answer

just to add little bit here 
this requires Implicit differentiation.  and for the second term derivative should be 
$$\Large \frac{d}{dx}\ln(y^2) =\frac{1}{y^2}*2y \frac{dy}{dx}$$.