Find the solutions to 0 > –(x – 2)^3
Here, eliminate the cube by taking the cube root of both sides.
Please help satelite.
\[0 > -(x -2)^3 \iff 0> -(x-2)\]
\[0>-(x-2)\] \[0>-x+2\] \[x>2\]
Isn't it x<2? You divided by negative #.
no did not divide lets go over the steps
\[0>-(x-2)\]use the distributive property to remove the parentheses get \[0>-x+2\]add \(x\) to both sides get \[x>2\]
Oh, I divided by -1
ok we can do that too start with \[0>-(x-2)\] divide (or multiply) by \(-1\) get \[0<x-2\] add 2 to get \[2<x\]
the method does not matter, you still end up with "\(x\) is greater than 2"
But I distributed the -1 and then I dvided by -1.
Why wouldn't that work?
ok we can do that as well \[0>-(x-2)\] \[0>-x+2\] subtract 2 get \[-2>-x\] divide by \(-1\) get \[2<x\]
Oh. Okay, thanks. So the answer is 2<x?
there is more than one say to skin a cat but the answer is still \(2<x\)
Okay, lol I only know one way to skin a cat though. lol
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