Trying to solve this with my ti 89 can someone help ???In one county, the conviction rate for DUI is 85%. Estimate the probability that of the next 100 DUI summonses issued, there will be at least 90 convictions.
is this a normal distribution? do we assume a mean of 0 and and sd of 1?
yes it is.
i have solved several like this i just need help getting started again
"the next 100" sounds more like a Poisson distribution to me .....
Estimate the indicated probability by using the normal distribution as an approximation to the binomial distribution
would it be a binomial cdf ??
it could be, but they seems to want the normal approximation to it instead
hmmmmm
success is .85 right? fail is then .15
and the term "at least" is important
that would be 90 or more
yes, and our sample size n is 100
i have the ti 89 calc. with the stats list editor app i know it can solve this
i never got fancy enough to play on a ti89; my class used the ti83
mean = n*success; mean = 85 in this case
and sd = sqrt(n*success*fail) sqrt(85*.15) = sqrt(12.75) = 3.571
i think the rest is just using the normalCDF function now
or just plug those right into the normalCDF nCDF(low, high, mean, sd) (90,9999,100*.85,sqrt(100*.85*.15))
so standard deviation is 3.571
i recall some caveat about making it a halfway point for the low or high tho to lessen the error
the function will work out the math for you if you just plug in the mathing :)
i put from 90 to infinity
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