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OpenStudy (vishweshshrimali5):
Please help me with this question
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OpenStudy (vishweshshrimali5):
@mukushla
@amistre64
@AravindG
I want help with question no. 31
OpenStudy (vishweshshrimali5):
@waterineyes
@experimentX
@eliassaab
Sorry to disturb u all.......
actually i m about to complete my exercise...
OpenStudy (anonymous):
Which one or all ???
OpenStudy (vishweshshrimali5):
only 31
OpenStudy (anonymous):
I got it..
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OpenStudy (anonymous):
show that\[2 \sec^2 a -\sec^4 a=2(1+\tan^2 a)-(1+\tan^2 a)^2=1-\tan^4 a\]
simplify other part with \(\text{cosec}\) like this to get ur answer
OpenStudy (vishweshshrimali5):
Ok thanks a lot @mukushla
U helped me again......
OpenStudy (anonymous):
yw :)
OpenStudy (anonymous):
Start by taking common;
\[cosec^2(x)(cosec^2(x) -2) - \sec^2(x)(\sec^2(x) - 2)\]
\[cosec^2(x)(\cot^2(x) - 1) - \sec^2(x)(\tan^2(x) -1)\]
\[-(1 + \cot^2(x))(1 - \cot^2(x)) + (1 + \tan^2(x))(1 - \tan^2(x))\]
\[\implies 1 - \tan^4(x) -1 + \cot^4(x) \implies \cot^4(x) - \tan^4(x)\]
OpenStudy (vishweshshrimali5):
Another nice method.......
Thanks @waterineyes
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OpenStudy (anonymous):
Using:
\[cosec^2(x) -1 = \cot^2(x)\]
\[\sec^2(x) -1 = \tan^2(x)\]
\[(a +b)(a-b) = a^2 - b^2\]
OpenStudy (anonymous):
Welcome..
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