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Mathematics 15 Online
OpenStudy (vishweshshrimali5):

Please help me with this question

OpenStudy (vishweshshrimali5):

@mukushla @amistre64 @AravindG I want help with question no. 31

OpenStudy (vishweshshrimali5):

@waterineyes @experimentX @eliassaab Sorry to disturb u all....... actually i m about to complete my exercise...

OpenStudy (anonymous):

Which one or all ???

OpenStudy (vishweshshrimali5):

only 31

OpenStudy (anonymous):

I got it..

OpenStudy (anonymous):

show that\[2 \sec^2 a -\sec^4 a=2(1+\tan^2 a)-(1+\tan^2 a)^2=1-\tan^4 a\] simplify other part with \(\text{cosec}\) like this to get ur answer

OpenStudy (vishweshshrimali5):

Ok thanks a lot @mukushla U helped me again......

OpenStudy (anonymous):

yw :)

OpenStudy (anonymous):

Start by taking common; \[cosec^2(x)(cosec^2(x) -2) - \sec^2(x)(\sec^2(x) - 2)\] \[cosec^2(x)(\cot^2(x) - 1) - \sec^2(x)(\tan^2(x) -1)\] \[-(1 + \cot^2(x))(1 - \cot^2(x)) + (1 + \tan^2(x))(1 - \tan^2(x))\] \[\implies 1 - \tan^4(x) -1 + \cot^4(x) \implies \cot^4(x) - \tan^4(x)\]

OpenStudy (vishweshshrimali5):

Another nice method....... Thanks @waterineyes

OpenStudy (anonymous):

Using: \[cosec^2(x) -1 = \cot^2(x)\] \[\sec^2(x) -1 = \tan^2(x)\] \[(a +b)(a-b) = a^2 - b^2\]

OpenStudy (anonymous):

Welcome..

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