Question

Can anyone help me solve the following trig equation

((sin75-sin15))/((cos75+cos15))=square root(3)/3

Answer 1

My work thus far has been 2cos(1/2)(75+15)sin(1/2)(75-15)/((2cos1/2(75+15)cos1/2(75-15))

Answer 2

sina- sinb = 2 cos(a+b/2)sin(a-b/2)
cosa+cob=2cos(a+b/2)cos(a-b/2) use these formula

Answer 3

I got 2square root(2)/2(1/2)/(square root(2)/2) square root(3)/2

Answer 4

yes do cancellations in numerator and in denominbator if any

Answer 5

Its simple... U have to know the conversion to sum or difference from the product or vice versa....
Sin75-Sin15= 2Cos(75+15)/2*Sin(75-15)/2 U will get 2cos45Sin30
now, Cos 75+Cos15=2Cos(75+15)/2*Cos(75-15)/2 U will get 2cos45Cos30
divide these two as in the question...... U will get 1/Squareroot3 which also equals square root(3)/3

Answer 6

I see now thanks waleed.

Answer 7

My pleasure @homeylova223