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OpenStudy (anonymous):
Identity help!!
tan2x=
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OpenStudy (anonymous):
identity means wat? @madigrieve
OpenStudy (anonymous):
a true relation?
OpenStudy (anonymous):
\[\tan(2x) = \frac{2 \tan(x)}{1 - \tan^2(x)}\]
OpenStudy (anonymous):
how did you get that?
OpenStudy (anonymous):
This is the basic identity..
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
Or I can show you if you want..
OpenStudy (anonymous):
i get that one now
OpenStudy (anonymous):
ill post another problem hold on
OpenStudy (anonymous):
tan (A + B) = (tan A + tan B)/(1 - (tan A)(tan B))
u can write tan2 x=tan(x+x) now plug a=b=x
thus tan(2x)=2tan(x)/1−tan2(x)
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OpenStudy (anonymous):
OpenStudy (anonymous):
Remember there is another formula:
\[\tan(x +y) = \frac{\tan(x) + \tan(y)}{1 - \tan(x) \cdot \tan(y)}\]
here replace y by x..
OpenStudy (anonymous):
oh ok i get the tan one now!
OpenStudy (anonymous):
that is true...
\[\frac{1}{2}(\sin(x) \cos(y) + \cancel{\cos(x) \sin(y)} + \sin(x) \cos(y) - \cancel{\cos(x) \sin(y)})\]
\[\implies \frac{1}{2}(2 \sin(x) \cos(y)) \implies \color{blue}{\sin(x) \cos(y)}\]
OpenStudy (anonymous):
thank you so much!!
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OpenStudy (anonymous):
Welcome dear..
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