Question

Write as a single log: (log3^x + log3^12) - log3^2

Answer 1

Hint: logA+logB-logC = log((A*B)/C)

Answer 2

use laws of logs:
log a + log b = log ab
log a - log b = log a/b
log^(na) = n log a

Answer 3

True. Just a bit of adjustment, right @cwrw238? log a^n = n log a

Answer 4

yea - sorry log a^n = n log a

Answer 5

so it is log(3x*3x^12)(3^2)

Answer 6

Hmm, not quite.
log3^x + log3^12- log3^2
Combining the first two, log(3^x*3^12)-log3^2
Then combining those gives: log((3^x*3^12)/3^2)

Answer 7

=(x+12)/2