Use synthetic division and the factor theorem to match the polynomial with its correct factor. x^3 + x^2 + 13x +4 x^3 - x +6 x^3 + x^2 - 3x +9
answers x + 4 x + 2 x+3 no factor listed for this polynomial
this is a lot of donkey work you want to do it the snap way?
\(x^3 + x^2 + 13x +4 \) doesn't have any factors with integers
sorry its just that this is my last work in its like 20 questions
in i want to get it done so i can be over with it
i understand i am just saying that this requires several steps of synthetic division, which is easy but a pain so it is easier to factor each polynomial
\[x^3-x+6=(x+2) (x^2-2 x+3)\]so you see the factor right away
ok im lost
you are asked to match the polynomial with its factor
hold on i screwed up sorry
i meant since \(x^3-x+6=(x+2) (x^2-2 x+3)\) you know that \(x+2\) is a factor of \(x^3-x+6\)
so you can match up \(x+2\) with \(x^3-x+6\)
it is a weird way to ask the question
similarly \(x^3 + x^2 - 3x +9 =(x+3) (x^2-2 x+3)\) so you can match up \(x+3\) with \(x^3 + x^2 - 3x +9 \)
that is all you can do for this one
IN THEN x^3 + x^2 + 13x +4 FOR no factor listed for this polynomial
yes
let me make sure hold on one second
ok
here you can see for yourself that it does not factor http://www.wolframalpha.com/input/?i=x^3+%2B+x^2+%2B+13x+%2B4+
thanks
yw 19 to go
Match the polynomial with its degree or the function with its value f(x) = x^2 - 3x + 3 g(x) = 2x^2 -1 g(3) f(z^2) f(4) x^4 + 3x^2 -5x 5x^10 + 13x^4 -17x^3 g(w^3) f(z) 5x^2 - 3x^5 -5x^3
Choose... 7 2w6 -1 z4 -3z2 +3 4 17 z2 -3z +3 10 5
can u help!!
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