PLEASE HELP What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
(1 point)
(x – 2)2 + (y – (–5))2 = 25
(x – (–2))2 + (y – 10)2 = 241
(x – 2)2 + (y – (–5))2 = 241
(x – (–2))2 + (y – 10)2 = 25

Question

PLEASE HELP What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
 (1 point)
(x – 2)2 + (y – (–5))2 = 25
(x – (–2))2 + (y – 10)2 = 241
(x – 2)2 + (y – (–5))2 = 241
(x – (–2))2 + (y – 10)2 = 25

campbell_st · Answer

find the distance from the centre (2, -5) to the point (-2, 10) which is on the circumference this will be the radius. 

The general form of the circle is 

$$(x -h)^2 + (y -k)^2 = r^2$$

(h, k) is the centre and r is the radius.

campbell_st · Answer

so the partial equation is 

$$(x - 2)^2 + (y - (-5))^2 = r^2$$

jkbo · Answer

i need help solving it please

jkbo · Answer

@campbell_st

campbell_st · Answer

do you know the distance formula..?

jkbo · Answer

no i just dont get how to solve the equation

jkbo · Answer

ok i solved it and i got B. @campbell_st

jkbo · Answer

is that right?