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Mathematics 15 Online
OpenStudy (anonymous):

give the formula for the unit vector which bisects the (smaller) angle between vector u and v

OpenStudy (anonymous):

\[ \mathbf{u}\text{ and } \mathbf{v}\] is arbitrary n-vector

OpenStudy (anonymous):

\[\frac { 1 }{ 4 } (|v\quad +\quad u{ | }^{ 2 }-|v\quad -\quad u{ | }^{ 2 }\quad =\quad u\quad *\quad v\\ (Use\quad the\quad notation\quad \hat { u } for\quad the\quad unit\quad vector\quad \IN\quad the\quad u-direction.) \]

OpenStudy (anonymous):

that is a scalar product, it doesn't produce the vector I need

OpenStudy (anonymous):

\[\\ Use\quad the\quad notation\quad \hat { u } for\quad the\quad unit\quad vector\quad IN\quad the\quad u-direction. \]

OpenStudy (anonymous):

it produces vevtor

OpenStudy (anonymous):

sorry vector

OpenStudy (anonymous):

how come can a scalar product produces a vector?? scalar product doesn't have a direction

OpenStudy (anonymous):

and no I'm talking about u and v of arbitrary magnitude so u does not necessarily equal v

OpenStudy (anonymous):

@IllasMcKay , this is a different question from mit exercise

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