Question

Challenge: Prove Fermat's Last Theorem in just one post.
No link pasting.

Answer 1

then copy from the webpage and paste

Answer 2

Okay, do that.

Answer 3

Fermat's Last Theorem states that no three positive integers a, b, and c can satisfy the equation an + bn = cn for any integer value of n greater than two.

Answer 4

Proof? And it's not an, but \(a^n\).

Answer 5

the general proof for all n required only that the theorem be established for all odd prime exponents.[49] In other words, it was necessary to prove only that the equation an + bn = cn has no integer solutions (a, b, c) when n is an odd prime number. This follows because a solution (a, b, c) for a given n is equivalent to a solution for all the factors of n. For illustration, let n be factored into d and e, n = de. The general equation
an + bn = cn
implies that (ad, bd, cd) is a solution for the exponent e
(ad)e + (bd)e = (cd)e.
Thus, to prove that Fermat's equation has no solutions for n > 2, it suffices to prove that it has no solutions for at least one prime factor of every n. All integers n > 2 contain a factor of 4, or an odd prime number, or both. Therefore, Fermat's Last Theorem can be proven for all n if it can be proven for n = 4 and for all odd primes (the only even prime number is the number 2) p.

Answer 6

It's not an + bn = cn, but it is \(a^n + b^n = c^n\).